Last post wins.
11-05-2013, 03:25 PM
Post: #820
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RE: Last post wins.
It's not g times 64, it's a subscript. It's basically a recursively defined function. g subscript 1 equals 3↑↑↑↑3, and g subscript n is defined based upon g subscript n-1. So g subscript 64 equals 3[↑^(g subscript 63)]3, so then that's 3[↑^(3[↑^(g subscript 62)]3)]3, which expands to 3[↑^(3[↑^(3[↑^(g subscript 61)]3)]3)]3, and so on...
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