Bongard Problems

[TheGreatErenan]

(03-17-2014 09:19 AM)[PETA] Doodat Wrote:  

(03-17-2014 08:43 AM)TheGreatErenan Wrote:  

(03-17-2014 06:01 AM)[PETA] Doodat Wrote:  Group A:
1010101
101
11110
10000000001
0

Group B:
1
110011
101010
10101

Group A: Evenly divisible by 101.
Group B: Not evenly divisible by 101.

???

I guess it works that way xD. That's interesting:
It's the same as saying that, changing the numbers from binary, they would be divisible by 5.

Yeah, I actually meant it in binary, though by coincidence it's true in this case in decimal as well. Every number in Group A treated as decimal is divisible by decimal 101. And every number in Group B (as decimal) is not divisible by decimal 101.

This isn't always true:

Binary 1100011 = decimal 99

Binary 1100011 (dec 99) is divisible by binary 1001 (dec 9).

But dec 1100011 isn't divisible by dec 1001.